Using Householder’s transformation, reduce the following matrices in tridiagonal form and find all the eigen values and eigen vectors. Write the strum sequence.
\(\left[ \begin{array}{cc} 1&2&2 \\ 2&1&2 \\2&2&1 \end{array} \right]\)
Adv.
\(\left[ \begin{array}{cc} 1&\sqrt{2}&\sqrt{2} &2\\ \sqrt{2}&-\sqrt{2}&-1&\sqrt{2}\\\sqrt{2} &-1&\sqrt{2}&\sqrt{2}\\ 2&\sqrt{2}&\sqrt{2}&-3 \end{array} \right]\)
If the orthogonal transform is of the form \(p=1-2WW^T\) where \(W\) is a column vector such that \(W^TW=1\). Prove that \(P\) is symmetric and orthogonal.
Write the strum sequence and find the eigen values of following matrix:
\(\left[ \begin{array}{cc} 1&-1&0&0&0&0 \\ 1&1&-1&0&0&0 \\ 0&1&1&-1&0&0 \\ 0&0&1&1&-1&0 \\0&0&0&1&1&-1 \\ 0&0&0&0&1&1\end{array} \right]\)
Use LR and QR both the methods to find the eigen values of the following matrix:
\(A =\left[ \begin{array}{cc} 3&2 \\ 1&4 \end{array} \right]\)
Let \(R\) be a ring in which \(a^2=a, \forall a \in R\) (such a ring is called a Boolean ring). Show that \(2a=0, \forall a\in R\) , and \(R\) is commutative. Further show that the only Boolean ring that is an integral domain is \(\mathbb{Z_2}\).
Let \(R\) be a ring and \(a,b \in R\)such that \(ab=ba\) . Prove that for any positive integer \((a+b)^n =a^n +\left( \begin{array}{c} n \\ 1 \end{array} \right)a^{n-1}b+ \cdots +\left( \begin{array}{c} n \\ n-1 \end{array} \right) ab^{n-1}+b^n\) .
Let \(d\) be any integer. Prove that \(\mathbb{Z}[\sqrt{d}] =\{a+b\sqrt{d} \; |a.b \in \mathbb{Z} \}\) is an integral domain and \(\mathbb{Z}[\sqrt{d}] =\{a+b\sqrt{d} \; |a.b \in \mathbb{Z} \}\) is a field.
Show that any ring with 6 elements is commutative.
If a non-zero subring \(S\) of a ring \(R\) has an identity \(1^\prime\) but \(R\) has either no identity or the identity of \(R\) is different from \(1^\prime\) , then show that \(1^\prime\) is a zero-divisor in \(R\) .
Prove that all the non-zero elements in an integral domain have same additive order, which is the characteristic of \(R\) if char \(R >0\)and infinite if char \(R=0\) .
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