The resultant  of two forces P and Q is perpendicular to P ; the resultant of P and Q' acting at same angle is perpendicular toQ' . prove that P is the geometric mean between Q and Q'.

Two forces P and Q have a resultant R. If the forces P be increased , then the new resultant bisects the angle between R and P . Find the increase in P.

The resultant R of the force P and Q makes an angle \(2\theta\) with the line of acting of P. P is now replaced by P+R , Q remaining unchanged . Show that the resultant makes an angle \(\theta\) with  P.

If the greatest  possible resultant of two forces P and Q is n times the least , showthat the angle \(\alpha\) between P and Q when their resultant is twice the squere root of their product is given by \(tan^2{\alpha}/2\) =\({1 \over n^2-2}\).

Two forces P,Q act at a point along two straight lines making an angle \(\alpha\) with each other and R is their resultant . Two other forces P', Q' acr along the same two lines and have a resultant R'. prove that the angle between the line of acting  the resultant is 

   \(\cos^{-1} \)(PP'+QQ'+(PQ'+P'Q)cos\(\alpha\))/RR'.

Two forces P and Q act an angle \(\alpha\) and having a resultant R . if each forces is increase by R , prove that the new resultant makes with R an angle 

\(\tan^{-1}\)\((P-Q)sin\alpha\over(P+Q+R+(P+Q)cos\alpha)\)

अनुच्छेद 243 का वर्णन करो?

Write about article 243.

Who was first govrner of bangal?

Cos A+ cos B=??

SinA+sinB=??