Find the value of
(9!+3!)/3!
Adv.
Find the value of tanA. If A =135°
A force of magnitude 24N is inclinded at an angle of \(30^\circ\) to the horizontal. Find its resolved parts in horizontal and verticle directions.
Find the component of a force P along two direction making angle \(45^\circ and 30^\circ\) with its on opposite sides.
A given force P resolved into two components inclinded \(45^\circ\) and \(\alpha\) .If the component is \({\sqrt{2} \over \sqrt3}\)P find \(\alpha\) and the other components.
The resolved part of a force F in a direction is \(\sqrt3\over2\)F. Find its inclinded with the force .Also find the other resolved parts.
Find the resolved part of a force is equal to 60kg.wt. in a direction making an angle equal to \(tan^{-1}{3\over4}\), Find the magnitude of the force . Also find its other resolved parts.
A force F resolved into two components. if one ofthe components is at right angle to the force and equal to it in magnitude , Find the direction and magnitude of the othe component.
AD is the altitude of tringle ABC. show that the force AD has a component along AB and AC equal to \(a^2+b^2+c^2\over2a^2 \) AB and\(c^2+a^2+b^2\over2a^2\) AC.
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