Two  parallel force of magnitude 12N and 8N act at two points 45cm apart on a rigid body . Find the magnitude , direction  and the position of application of their resultant when the force are 

1) like 

2) unlike

The resultant of two parallel forces whose  line of action are 12 m apart  and act in opposite sense is 700 N. if the resultant act at 3m from the forces , what are the forces ?

The resultant of two like parallel forces P and Q acting at point A and B aparts , 40 N . If the resultant passes through C,  where AC=3cm , Find the magitude of the forces .Also  show that if the forces where interchanged , the resultant  shifts through a distance of 2cm.

If the position of the resultant of two like paraallel forces remains unaltered when their positions are interchanged , show that the froces are equal.

A light rod ,12 cms long is suspended in a horizontal position by mean of two verticle strings. One string can stand a tension of 10gms and other of 20gms . a ring weighing 25gms can slide along the rod. find the least distance of the ring fromthe string .

Two likr paarallel forces P and Q act a given point of a body . If Q be changed to \(P^2\over{Q}\), show that the line of action of the resultant is the same as it would be if the forces were simply interchanged.

Two like parallel forces P and Q act at points A and B of a body .Their resultant meets AB in C .When the forces are interchanged , the resultant meet AB in D . if AC=DC , show that \(P:Q::2:1\)

The resultant of two like parallel forces P and Q passes through a point O .when P is incresed by R and Q by S , the resultant still passes through O and also when Q,R replaced P,Q respectively. show that

\(S={Q^2\over{P^2}}=R-{(Q-R)^2\over(P-Q)}.\)

Two unlike parallel forces P and Q (P>Q) act at A and B resp. if P and Q both increased by x show that the resultant will move through a distance \(xAB\over{P-Q}\)

P and Q are two like parallel forces . IF P be moves parallel to itself through a disance x, show that their resultant moves through a distance 

\(Px\over{P+Q}\)

P and Q are two parallel forces . Even on increasing them by x and y respec. the position of their resultant does not changed . prove that 

P:Q::x:y.