Class 9 Homework-

Test—CI connection In exercise 1, explain how the result of the 99% confidence interval in part b corresponds to the result of the decision using significance level 0.01 in part c.

Exercise 1

Time spent on Internet In 2006, the General Social Survey asked about the number of hours a week spent on the World Wide Web (variable denoted WWWTIME). Some results are as follows:

Group

N

Mean

StDev

SE Mean

Male

1196

6.2

9.9

0.285

Female

1569

4.9

8.6

0.216

Difference = mu(Male) − mu(Female)

Estimate for difference: 1.3

99% CI for difference: (0.4. 2.2)

T-Test of difference = 0 (vs not =):

T-value = 3.62 P-value = 0.000

a. Identify the response variable and explanatory variable. Indicate whether each variable is quantitative or categorical.

b. Report and interpret the 99% confidence interval shown for the difference between the population means for males and females.

c. Report and interpret the steps of the significance test comparing the two population means. Make a decision, using significance level 0.01.




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