Test—CI connection In exercise 1, explain how the result of the 99% confidence interval in part b corresponds to the result of the decision using significance level 0.01 in part c.
Exercise 1
Time spent on Internet In 2006, the General Social Survey asked about the number of hours a week spent on the World Wide Web (variable denoted WWWTIME). Some results are as follows:
Group |
N |
Mean |
StDev |
SE Mean |
Male |
1196 |
6.2 |
9.9 |
0.285 |
Female |
1569 |
4.9 |
8.6 |
0.216 |
Difference = mu(Male) − mu(Female) |
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Estimate for difference: 1.3 |
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99% CI for difference: (0.4. 2.2) |
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T-Test of difference = 0 (vs not =): |
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T-value = 3.62 P-value = 0.000 |
a. Identify the response variable and explanatory variable. Indicate whether each variable is quantitative or categorical.
b. Report and interpret the 99% confidence interval shown for the difference between the population means for males and females.
c. Report and interpret the steps of the significance test comparing the two population means. Make a decision, using significance level 0.01.