A number when divided successively by 4 and 5 leaves remainders 1 and 4 respectively. When it is successively divided by 5  and 4 then the respective remainders will be ?

 Find the solution :

\(\frac{1^{93}+2^{93}+------+89^{93}}{90}\)

Solve :

\(\frac{2^{100}}{102}\) find Reminder ?

\(87^{2002} \) find last 3 digit .

Find last 2 digit :

\(43^{362}\)

Find remainder :-

\(\frac{10^{1}+10^{2}+10^{3}+--------+10^{100}}{6}\)

Find Reminder:

\(\frac{10^{4}+-----+30times}{7}\)

Find reminder

\(\frac{10^{10^{1}}+10^{10^{2}}+10^{10^{3}}+----+10^{10^{30}}}{7}\)

Find remainder 

\(\frac{35^{33^{31}}}{16}\)

Find the value of remainder

\(\frac{113^{97^{96}}}{97}\)

Find the value of remainder:

\(\frac{15^{30^{45}}}{8}\)