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Solve the system of equations

\(2x_{1}+x_{2}+2x_{3}+x_{4}=6\)

\(4x_{1}+3x_{2}+3x_{3}-3x_{4}=-1\)

\(6x_{1}-6x_{2}+6x_{3}+12x_{4}=36\)

\(2x_{1}+2x_{2}-x_{3}+x_{4}=10\)


Adv.

Answer:




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