A packet contains some red pens, blue pens and black pens such that the probability of picking a red pen is 3/13 and probability of picking a black pen is 1/3. If no. of blue pens is 17 and if all the pens are numbered starting from 1,2,3,….. and so on , then what is the probability of getting one pen numbered as multiple of 5 or 8 ?

A \(\frac{2}{3}\). B \(\frac{3} {52} \). C \(\frac{3}{13}\) D. \(\frac {11} {39}\) E. \(\frac{10} {39}\)

Adv.

Answer:

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