Consider the differential equation \(y'=y^2-1\), x > 0 together with initial condition y(0) = \(y_0\) Then for −1 < \(y_0\) < 1, all the solutions y(x) are such that:
(a) y → −∞ as x → ∞.
(b) y → −1 as x → ∞.
(c) graph of y(x) is concave downwards.
(d) graph of y(x) is concave upwards.