\(1\frac{1}{2}+4\frac{1}{6}+7\frac{1}{12}+10\frac{1}{20}\) up to 20th term. Here 20th term is 58. Find the sum?

Evaluate:

\(\frac{1}{1*3*5}+\frac{1}{1*4}+\frac {1}{3*5*7}+\frac{1}{1*4}+\frac{1}{5*7*9}+\frac{1}{7.10} \)

up to 20 th term .

\(\frac {1}{1*2*3*4}+ \frac{1}{2*3*4*5}+----+\frac{1}{15*16*17*18}\)

Find the solution.

Find the solution:

\(\frac{1}{5*10*15}+\frac{1}{10*15*20}+\frac{1}{15*20*25}+---+\frac{1}{150*155*160}\)

30th term. Find 30th term?

\(\frac{1}{1*4*7}+\frac{1}{4*7*10}+\frac{1}{7*10*13}+\frac{1}{10*13*16}+\frac{1}{13*16*19}\)

\(\frac{1}{1*2}+\frac{1}{1*4}+\frac{1}{2*3}+\frac{1}{3*4}+\frac{1}{7*10}+---+\)

20th term?

Evaluate :

\(\frac{1}{7^2-3^2}+\frac{1}{13^2-3^2}+\frac{1}{19^2-3^2}+---+\frac{1}{49^2-3^2}\)

\(\frac{1}{2^2-1}+\frac{1}{4^2-1}+\frac{1}{6^2-1}+---+\frac{1}{20^2-1}\)

\(\frac{1}{2*5}+\frac{1}{5*8}+\frac{1}{8*11}+---+\frac{1}{299*302}\)

\(\frac{1}{3*7}+\frac{1}{7*11}+\frac{1}{11*15}+---+\frac{1}{899*903}\)

\(\frac{1}{1*2}+\frac{1}{2*3}+\frac{1}{3*4}+---+\frac{1}{99*100}\)

Evaluate :\(\frac{222-----------9times}{9}\)

\(\frac{1111--------243times}{243}\)

\(\frac{8888----------75times}{37}\)

64329 is divided by a number then their are 3 consecutive reminders 175,114 and 213. Find the sum of digit of that divisors.

A number when divided successively by 4 and 5 leaves remainders 1 and 4 respectively. When it is successively divided by 5 and 4 then the respective remainders will be ?

Find the solution :

\(\frac{1^{93}+2^{93}+------+89^{93}}{90}\)

Solve :

\(\frac{2^{100}}{102}\) find Reminder ?

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∫2xcos(x2 – 5).dx

If the sum of 14 terms of an A. P is 1050 its first term is 10 find 20th term ?

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A cyclic quadrilateral pqrs are where PS equals to PQ and angle SPQ is 70 degree find angle psq