Energy conservation is very important today because -

1) Sources of conventional energy are fast debleting

2) Electrical energy has become more expensive

3) Electrical energy consumption is increasing

4) None of the above

To sum the numbers 1.53, .006, .1223; which are correct as they are given. Find absolute and relative error.

Computing x1x2 and x1/x2 for x1=2.48, x2=3.4415, evaluate the relative and absolute error. Further comment on the accuracy of the result.

Why the calculations through calculator are approximate?

Using Power method, obtain the largest eigen value and corresponding eigen vector correct upto 2d of the following matrices:

1. \(\left[\begin{array}{ccc} 1&2&-1 \\ 2&1&2 \\ -1&2&1\end{array}\right]\)   
2. \(\left[\begin{array}{ccc} 4&1&1&1 \\ 3&-1&1&1\\ -1&1&2&0\\1&1&0&2\end{array}\right]\)

       3. \(\left[\begin{array}{ccc} 0&11&-5\\ -2&17&-7 \\ -4&26&-10\end{array}\right]\)

Find the smallest eigen value and corresponding eigen vector of the following matrices using Power method:

1. \(\left[\begin{array}{ccc} 3&2&1 \\ 2&3&2 \\ 1&2&2\end{array}\right]\)
2. \(\left[\begin{array}{ccc} 2&2&-1 \\ -5&9&-3 \\ -4&4&1\end{array}\right]\)
3. \(\left[\begin{array}{ccc} 2&-1&0 \\ -1&2&-1 \\ 0&-1&2\end{array}\right]\)

Find all the eigen values and corresponding eigen vectors using Power method:

1. \(\left[\begin{array}{ccc} 1&2&3 \\ 3&1&0 \\ -2&0&1\end{array}\right]\)
2. \(\left[\begin{array}{ccc} 4&1&0\\ 1&20&1 \\ 0&1&4\end{array}\right]\)
3. \(\left[\begin{array}{ccc} 2&1&1&0 \\ 1&1&0&1 \\ 1&0&0&1\\1&1&1&2\end{array}\right]\)

If the largest eigen value of the matrix\(\left[\begin{array}{ccc} 5&-2&0 \\ 1&2&-3 \\ 1&-2&4\end{array}\right]\)is 6 and corresponding eigen vector is\(\left[\begin{array}{ccc} 1 \\ -1/2 \\ 1\end{array}\right]\),then find the subdominant eigen value.

Find the eigen values of following matrix:

\(\left[\begin{array}{ccc} 1&-1&0&0&0&0 \\ 1&1&-1&0&0&0 \\ 0&1&1&-1&0&0\\0&0&1&1&-1&0\\0&0&0&1&1&-1\\0&0&0&0&1&1\end{array}\right]\)

Let y(x) be a continuous solution of the initial value problem

y' + 2y = f(x), y(0) = 0, where \( f(x) = \begin{cases} 1, & \quad \text{if } 0 \le x\le1,\\ 0, & \quad \text{if } x>1 \end{cases} \)

Then y\(( \frac{3}{2})\) is equal to

(a)  \(( \frac{sinh(1)}{e^3})\)  (b)   \(( \frac{cosh(1)}{e^3})\)   (c)  \(( \frac{sinh(1)}{e^2})\)  (d)   \(( \frac{cosh(1)}{e^2})\)